Section 1 — This section contains FOUR (04) questions. Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four option(s) is(are) correct answer(s).
A uniform solid cylinder of mass and radius is rolling without slipping on a horizontal surface with velocity . It encounters a sharp edge (step) of height (where ). Assume the cylinder does not slip at the edge and the collision with the edge is perfectly inelastic (the cylinder pivots about the edge). Which of the following statement(s) is(are) correct?
Select Option(s) [One or more may be correct]:
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Step-by-Step Solution & Derivations
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Flagship Physics Simulation: Rolling Cylinder Pivoting Over Step
Analytical Mechanics
Phase 1: Rolling (v₀)
Climbing Threshold Will Climb
Current v₀:3.20 m/s
v₀,min threshold:1.75 m/s
Post-impact ω₁:5.12 rad/s
Impact Energy Loss:36.0%
t: 0.00s
Speed:
Initial Velocity (v₀)3.20 m/s
0.5 m/s7.0 m/s
Cylinder Radius (R)0.50 m
0.2 m1.2 m
Step Height (h < R)0.15 m
0.05 m0.45 m
Cylinder Mass (M)2.0 kg
0.5 kg5.0 kg
KE Before Collision:15.4 J
KE After Collision:9.8 J
🔴 36.0% kinetic energy lost in inelastic collision
Angular Momentum (L_edge):CONSERVED ✓
L_before = 3.84 kg·m²/s
I_edge · ω₁ = 3.84 kg·m²/s
Reaction force at edge has zero torque about edge itself.